What is the volume in mL that corresponds to 10 g of Lactulose if it is available as 40 g in 60 mL?

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To determine the volume in mL that corresponds to 10 g of Lactulose based on a concentration of 40 g in 60 mL, first, we need to find the concentration of the solution.

The concentration can be calculated by finding out how many grams are in 1 mL. Since there are 40 g in 60 mL, we can set up a proportional relationship:

Concentration = 40 g / 60 mL = 0.67 g/mL (approximately)

Next, to find out how many mL correspond to 10 g of Lactulose, we set up the following equation:

Volume (mL) = Amount (g) / Concentration (g/mL)

Plugging in the values:

Volume (mL) = 10 g / 0.67 g/mL ≈ 15 mL

This means that for every 10 g of Lactulose, approximately 15 mL of solution is required.

Thus, the answer corresponds well with the calculated needs, leading us to conclude that the volume of 40 mL is which will result in obtaining sufficient volume to attain the desired output. Since we need 10 g, and we recognize that it is less than

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